Loss Solution Formula



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Loss Solution Formula
Chemistry Question (about pH)?

I have a lab tomorrow, and I must do some prelab questions for the experiment. It's concerning acids and bases.

In the first question I wrote this reaction, (the first ionization of Phosphoric acid and water) which I think is correct:
H3PO4 + H2O ---> H3O+ + H2PO4-
Next I found the Ka1 constant for the reaction:
Kal= [H3O][H2PO4-] / [H3PO4]

The third question asks: "What would be the pH of the solution when [H3PO4]=[H2PO4-]?"
I do not yet understand the concept of pH very well, and thus I am not clear on what the question is asking; I also have these given values:

Ka1= 7.5 x 10 ^ -3
Ka2= 6.2 x 10 ^ -8
Ka3= 4.2 x 10 ^ -13

I understand what pH is, I just don't know how to use it; pH = -log[H3O], but I am at a loss as to how to utilize this formula.

Thank you!

Kal= [H3O+][H2PO4-] / [H3PO4]

When [H3PO4]=[H2PO4-] the above expression becomes Ka1=[H3O+] =7.5 x 10 ^ -3or 7.5E-3

pH =-log[H3O+]= -log(7.5E-3) =2.12

to do this -log(7.5E-3) depends on the calculator you have. I have a non graphing TI36X

I put in 7.5 EE the exponential key and -3 and enter. the answer is negative so I press the change sign key to get a positive answer

I just plugged it into google search and it calculated it for me correctly

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